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XyzWs Java FAQ:
Why label statement causes compile time error?
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Why label statement causes compile time error?The following code has compile time error and why?
public class Program {
public static void main(String[] args) {
int counter = 0;
label1:
for (int i=0; i!=10; i++) {
label2:
int j = 0; //compile time error
while (j++ < 10) {
if (j > i) break label2;
if (j == i) {
counter++;
continue label1;
}
}
}
System.out.println(counter);
}
}
From JLS:
The use of labels in loops and breaks has the following rules:
In the above example, there are two problems. The first one is that label2 can't be followed immediately by a declaration statement, this is a syntax error. If we add another statement before the int j =0; to fix the syntax error, so that:
public class Program {
public static void main(String[] args) {
int counter = 0;
label1:
for (int i=0; i!=10; i++) {
label2:
System.out.println(i);
int j = 0;
while (j++ < 10) {
if (j > i) break label2; //compile time error
if (j == i) {
counter++;
continue label1;
}
}
}
System.out.println(counter);
}
}
It unveils the second problem, label2 must be on the enclosing statement, otherwise the compiler thinks label2 is missing. We can fix the compiler error by simple adding parentheses to the above code. A group of statements enclosed in parentheses {}- called a code block - acts as a single statement. This way, label2 is on the whole enclosing statement.
public class Program {
public static void main(String[] args) {
int counter = 0;
label1:
for (int i=0; i!=10; i++) {
label2:
{ //
System.out.println(i);// the code compiles with or without this line
int j = 0;
while (j++ < 10) {
if (j > i) break label2;
if (j == i) {
counter++;
continue label1;
}
}
} //
}
System.out.println(counter);
}
}
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